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Simple Pendulum
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Speed
0.25×
0.5×
1×
2×
T
=
2
π
L
g
=
2
π
1
9.81
=
2.01
s
T = 2\pi\sqrt{\tfrac{L}{g}} = 2\pi\sqrt{\tfrac{1}{9.81}} = 2.01\,\text{s}
T
=
2
π
g
L
=
2
π
9.81
1
=
2.01
s
Period (T)
2.01 s
Length (L)
1 m
Mass (m)
1 kg
Gravity (g)
9.81 m/s²
Damping
0
Release from 30°
⬜
Tune the period to 1.5 seconds
⬜
Slow the swing to a period above 3 seconds
⬜
Set the period to exactly 2.5 seconds
⬜
Prove that mass does not affect the period
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